Boys' singles
1956 Wimbledon Championships
ChampionUnited States Ronnie Holmberg
Runner-upAustralia Rod Laver
Score6–1, 6–1

Ronnie Holmberg defeated Rod Laver in the final, 6–1, 6–1 to win the boys' singles tennis title at the 1956 Wimbledon Championships.[1]

Draw

Key

Finals

Semifinals Final
          
United States Ronnie Holmberg 6 8
Tunisia Mustapha Belkhodja 1 6
United States Ronnie Holmberg 6 6
Australia Rod Laver 1 1
Pakistan Mohammad Naeem 6 3 1
Australia Rod Laver 3 6 6

Top half

First round Second round Quarterfinals Semifinals
Austria O Mulli 1 1
United States Ronnie Holmberg 6 6
United States R Holmberg 7 6
West Germany W Bungert 5 4
Norway H Larsen 2 1
West Germany Wilhelm Bungert 6 6
United States R Holmberg 6 8
Tunisia M Belkhodja 1 6
India Akhtar Ali 6 6
Belgium G Gevers 4 3
India A Ali 1 1
Trinidad and Tobago Peter Valdez 5 5 Tunisia M Belkhodja 6 6
Sweden Jan Josefsson 7 7 Sweden J Josefsson 2 2
Netherlands Hans Biesheuvel 2 2 Tunisia M Belkhodja 6 6
Tunisia Mustapha Belkhodja 6 6

Bottom half

First round Second round Quarterfinals Semifinals
United Kingdom Mike Sangster 6 2 5
Czechoslovakia J Jelínek 3 6 7 Czechoslovakia J Jelínek 6 2 3
Monaco Adrien Viviani 3 1 Pakistan M Naeem 3 6 6
Pakistan Mohammad Naeem 6 6 Pakistan M Naeem 6 8
South Africa B Page 0 6
Switzerland Bruno Spielmann 2 1
South Africa Brian Page 6 6
Pakistan M Naeem 6 3 1
Australia R Laver 3 6 6
Denmark B Nyløkke 3 3
Australia Rod Laver 6 6
Australia R Laver 6 6
Socialist Federal Republic of Yugoslavia B Miletić 0 3
Republic of Ireland G Cleary 3 8
Socialist Federal Republic of Yugoslavia Bogdan Miletić 6 10

References

  1. "Boys' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.
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