Girls' singles
1962 Wimbledon Championships
ChampionSoviet Union Galina Baksheeva
Runner-upNew Zealand Elizabeth Terry
Score6–4, 6–2
Draw18

Galina Baksheeva successfully defended her title, defeating Elizabeth Terry in the final, 6–4, 6–2 to win the girls' singles tennis title at the 1962 Wimbledon Championships.[1]

Draw

Key

Finals

Semifinals Final
          
Soviet Union Galina Baksheeva 6 6
Denmark Birgit Grage 4 1
Soviet Union Galina Baksheeva 6 6
New Zealand Elizabeth Terry 4 2
New Zealand Elizabeth Terry 6 7 6
United Kingdom Sally Holdsworth 2 9 4

Top half

First round Second round Quarterfinals Semifinals
Finland Christina Lindström 2 1
Netherlands Anja Lepoutre 6 6
Netherlands A Lepoutre 8 1 1
Soviet Union G Baksheeva 6 6 6
Soviet Union Galina Baksheeva 6 6
Brazil L Fineberg 1 2
Soviet Union G Baksheeva 6 6
Denmark B Grage 4 1
Indonesia Lita Liem w/o
Poland D Makulska
Poland D Makulska 6 1
Denmark B Grage 8 6
Austria R Leyrer 3 4
Sweden E Hultkrantz 4 3 Denmark B Grage 6 6
Denmark Birgit Grage 6 6

Bottom half

First round Second round Quarterfinals Semifinals
Republic of Ireland A Keegan 2 4
New Zealand Elizabeth Terry 6 6 New Zealand E Terry 6 6
France Françoise Courteix 4 2
New Zealand E Terry 6 6
Belgium O Jacob 1 3
Belgium O Jacob 8 6
Switzerland I Gubler 6 1
New Zealand E Terry 6 7 6
United Kingdom S Holdsworth 2 9 4
British Guiana J Franker 1 1
United Kingdom Sally Holdsworth 6 6
United Kingdom S Holdsworth 6 8
Norway K Robsahm 3 6
Norway Kirsten Robsahm 2 6 6
Mexico C Hawley 6 4 4

References

  1. "Girls' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.
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