Doubles
1993 Hellmann's Cup
Champions
Runners-up
Score7–6, 6–4

This was the first edition of the event.

Mike Bauer and David Rikl won the title, defeating Christer Allgårdh and Brian Devening 7–6, 6–4 in the final.[1]

Seeds

  1. Spain Sergio Casal / Spain Emilio Sánchez (first round)
  2. Netherlands Mark Koevermans / United States Greg Van Emburgh (first round)
  3. Spain Tomás Carbonell / South Africa Byron Talbot (first round)
  4. Argentina Pablo Albano / Argentina Javier Frana (semifinals)

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1
3 3  
 
6 6    
6 7  
Q
3 4    
3 6  
 
6 6    
7 2 6
3
6 5 6  
6 6 2
WC
4 7 7 WC
6 3 3
 
6 6    
3 6 6
 
4 4    
6 4  
 
2 4    
7 6  
 
6 6    
6 3  
WC
  • Chile Robinson Gamonal
  • Chile Francisco Ruiz
3 2   4
7 6  
4
6 6   4
3 3  
 
7 6 3  
6 6  
 
6 7 6  
w/o    
 
6 6    
     
2
4 4  

References

  1. ↑ John Barrett, ed. (1994). International Tennis Federation World of Tennis 1994. London: CollinsWillow. p. 137. ISBN 9780002184564.
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