Doubles
2007 ATP Buenos Aires
Champions	Martín García Sebastián Prieto
Runners-up	Albert Montañés Rubén Ramírez Hidalgo
Score	6–4, 6–2

František Čermák and Leoš Friedl were the defending champions, but Čermák did not participate this year. Friedl partnered Michael Kohlmann, losing in the first round.

Martín García and Sebastián Prieto won the title, defeating Albert Montañés and Rubén Ramírez Hidalgo 6–4, 6–2 in the final.

Seeds

Draw

Draw

	First round							Quarterfinals							Semifinals							Final
	1	L Dlouhý P Vízner	77	63	[11]
		A di Mauro P Starace	63	77	[9]			1	L Dlouhý P Vízner	6	6
		T Cibulec J Vaněk	2	66					D Hartfield M Vassallo Argüello	3	2
		D Hartfield M Vassallo Argüello	6	78											1	L Dlouhý P Vízner	2	2
	3	L Friedl M Kohlmann	6	3	[8]											A Montañés R Ramírez Hidalgo	6	6
		A Montañés R Ramírez Hidalgo	0	6	[10]				A Montañés R Ramírez Hidalgo	w/o
		P Cuevas S Galvani	6	6					P Cuevas S Galvani
		N Almagro M Granollers-Pujol	3	2																			A Montañés R Ramírez Hidalgo	4	2
		N Devilder O Patience	7	7																		4	M García S Prieto	6	6
		A Martín F Vicente	5	5					N Devilder O Patience	3	2
	WC	E Schwank C Villagrán	4	6	[12]			4	M García S Prieto	6	6
	4	M García S Prieto	6	2	[14]										4	M García S Prieto	65	7	[11]
		M Melo A Sá	4	2											2	M Fyrstenberg M Matkowski	77	5	[9]
	WC	C Berlocq B Dabul	6	6				WC	C Berlocq B Dabul	5	6	[9]
		M González S Roitman	6	5	[5]			2	M Fyrstenberg M Matkowski	7	3	[11]
	2	M Fyrstenberg M Matkowski	4	7	[10]

References

• Main Draw