The digamma function ${\displaystyle \psi (z)}$,
visualized using domain coloring

Real part plots of the digamma and the next three polygamma functions along the real line

In mathematics, the digamma function is defined as the logarithmic derivative of the gamma function:^[1][2][3]

${\displaystyle \psi (z)={\frac {\mathrm {d} }{\mathrm {d} z}}\ln \Gamma (z)={\frac {\Gamma '(z)}{\Gamma (z)}}.}$

It is the first of the polygamma functions. This function is strictly increasing and strictly concave on ${\displaystyle (0,\infty )}$,^[4] and it asymptotically behaves as^[5]

${\displaystyle \psi (z)\sim \ln {z}-{\frac {1}{2z}},}$

for large arguments (${\displaystyle |z|\rightarrow \infty }$) in the sector ${\displaystyle |\arg z|<\pi -\varepsilon }$ with some infinitesimally small positive constant ${\displaystyle \varepsilon }$.

The digamma function is often denoted as ${\displaystyle \psi _{0}(x),\psi ^{(0)}(x)}$ or Ϝ^[6] (the uppercase form of the archaic Greek consonant digamma meaning double-gamma).

Relation to harmonic numbers

The gamma function obeys the equation

${\displaystyle \Gamma (z+1)=z\Gamma (z).\,}$

Taking the logarithm on both sides gives:

${\displaystyle ln(\Gamma (z+1))=\ln(z)+\ln(\Gamma (z)),}$

Differentiating both sides with respect to z gives:

${\displaystyle \psi (z+1)=\psi (z)+{\frac {1}{z}}}$

Since the harmonic numbers are defined for positive integers n as

${\displaystyle H_{n}=\sum _{k=1}^{n}{\frac {1}{k}},}$

the digamma function is related to them by

${\displaystyle \psi (n)=H_{n-1}-\gamma ,}$

where H₀ = 0, and γ is the Euler–Mascheroni constant. For half-integer arguments the digamma function takes the values

${\displaystyle \psi \left(n+{\tfrac {1}{2}}\right)=-\gamma -2\ln 2+\sum _{k=1}^{n}{\frac {2}{2k-1}}.}$

Integral representations

If the real part of z is positive then the digamma function has the following integral representation due to Gauss:^[7]

${\displaystyle \psi (z)=\int _{0}^{\infty }\left({\frac {e^{-t}}{t}}-{\frac {e^{-zt}}{1-e^{-t}}}\right)\,dt.}$

Combining this expression with an integral identity for the Euler–Mascheroni constant ${\displaystyle \gamma }$ gives:

${\displaystyle \psi (z+1)=-\gamma +\int _{0}^{1}\left({\frac {1-t^{z}}{1-t}}\right)\,dt.}$

The integral is Euler's harmonic number ${\displaystyle H_{z}}$, so the previous formula may also be written

${\displaystyle \psi (z+1)=\psi (1)+H_{z}.}$

A consequence is the following generalization of the recurrence relation:

${\displaystyle \psi (w+1)-\psi (z+1)=H_{w}-H_{z}.}$

An integral representation due to Dirichlet is:^[7]

${\displaystyle \psi (z)=\int _{0}^{\infty }\left(e^{-t}-{\frac {1}{(1+t)^{z}}}\right)\,{\frac {dt}{t}}.}$

Gauss's integral representation can be manipulated to give the start of the asymptotic expansion of ${\displaystyle \psi }$.^[8]

${\displaystyle \psi (z)=\log z-{\frac {1}{2z}}-\int _{0}^{\infty }\left({\frac {1}{2}}-{\frac {1}{t}}+{\frac {1}{e^{t}-1}}\right)e^{-tz}\,dt.}$

This formula is also a consequence of Binet's first integral for the gamma function. The integral may be recognized as a Laplace transform.

Binet's second integral for the gamma function gives a different formula for ${\displaystyle \psi }$ which also gives the first few terms of the asymptotic expansion:^[9]

${\displaystyle \psi (z)=\log z-{\frac {1}{2z}}-2\int _{0}^{\infty }{\frac {t\,dt}{(t^{2}+z^{2})(e^{2\pi t}-1)}}.}$

From the definition of ${\displaystyle \psi }$ and the integral representation of the gamma function, one obtains

${\displaystyle \psi (z)={\frac {1}{\Gamma (z)}}\int _{0}^{\infty }t^{z-1}\ln(t)e^{-t}\,dt,}$

with ${\displaystyle \Re z>0}$.^[10]

Infinite product representation

The function ${\displaystyle \psi (z)/\Gamma (z)}$ is an entire function,^[11] and it can be represented by the infinite product

${\displaystyle {\frac {\psi (z)}{\Gamma (z)}}=-e^{2\gamma z}\prod _{k=0}^{\infty }\left(1-{\frac {z}{x_{k}}}\right)e^{\frac {z}{x_{k}}}.}$

Here ${\displaystyle x_{k}}$ is the kth zero of ${\displaystyle \psi }$ (see below), and ${\displaystyle \gamma }$ is the Euler–Mascheroni constant.

Note: This is also equal to ${\displaystyle -{\frac {d}{dz}}{\frac {1}{\Gamma (z)}}}$ due to the definition of the digamma function: ${\displaystyle {\frac {\Gamma '(z)}{\Gamma (z)}}=\psi (z)}$.

Series representation

Reflection formula

The digamma function satisfies a reflection formula similar to that of the gamma function:

${\displaystyle \psi (1-x)-\psi (x)=\pi \cot \pi x}$

Recurrence formula and characterization

The digamma function satisfies the recurrence relation

${\displaystyle \psi (x+1)=\psi (x)+{\frac {1}{x}}.}$

Thus, it can be said to "telescope" 1 / x, for one has

${\displaystyle \Delta [\psi ](x)={\frac {1}{x}}}$

where Δ is the forward difference operator. This satisfies the recurrence relation of a partial sum of the harmonic series, thus implying the formula

${\displaystyle \psi (n)=H_{n-1}-\gamma }$

where γ is the Euler–Mascheroni constant.

More generally, one has

${\displaystyle \psi (1+z)=-\gamma +\sum _{k=1}^{\infty }\left({\frac {1}{k}}-{\frac {1}{z+k}}\right).}$

for ${\displaystyle \mathrm {Re} (z)>0}$. Another series expansion is:

${\displaystyle \psi (1+z)=\ln(z)+{\frac {1}{2z}}-\displaystyle \sum _{j=1}^{\infty }{\frac {B_{2j}}{2jz^{2j}}}}$,

where ${\displaystyle B_{2j}}$ are the Bernoulli numbers. This series diverges for all z and is known as the Stirling series.

Actually, ψ is the only solution of the functional equation

${\displaystyle F(x+1)=F(x)+{\frac {1}{x}}}$

that is monotonic on R⁺ and satisfies F(1) = −γ. This fact follows immediately from the uniqueness of the Γ function given its recurrence equation and convexity restriction. This implies the useful difference equation:

${\displaystyle \psi (x+N)-\psi (x)=\sum _{k=0}^{N-1}{\frac {1}{x+k}}}$

Some finite sums involving the digamma function

There are numerous finite summation formulas for the digamma function. Basic summation formulas, such as

${\displaystyle \sum _{r=1}^{m}\psi \left({\frac {r}{m}}\right)=-m(\gamma +\ln m),}$

${\displaystyle \sum _{r=1}^{m}\psi \left({\frac {r}{m}}\right)\cdot \exp {\dfrac {2\pi rki}{m}}=m\ln \left(1-\exp {\frac {2\pi ki}{m}}\right),\qquad k\in \mathbb {Z} ,\quad m\in \mathbb {N} ,\ k\neq m.}$

${\displaystyle \sum _{r=1}^{m-1}\psi \left({\frac {r}{m}}\right)\cdot \cos {\dfrac {2\pi rk}{m}}=m\ln \left(2\sin {\frac {k\pi }{m}}\right)+\gamma ,\qquad k=1,2,\ldots ,m-1}$

${\displaystyle \sum _{r=1}^{m-1}\psi \left({\frac {r}{m}}\right)\cdot \sin {\frac {2\pi rk}{m}}={\frac {\pi }{2}}(2k-m),\qquad k=1,2,\ldots ,m-1}$

are due to Gauss.^[15][16] More complicated formulas, such as

${\displaystyle \sum _{r=0}^{m-1}\psi \left({\frac {2r+1}{2m}}\right)\cdot \cos {\frac {(2r+1)k\pi }{m}}=m\ln \left(\tan {\frac {\pi k}{2m}}\right),\qquad k=1,2,\ldots ,m-1}$

${\displaystyle \sum _{r=0}^{m-1}\psi \left({\frac {2r+1}{2m}}\right)\cdot \sin {\dfrac {(2r+1)k\pi }{m}}=-{\frac {\pi m}{2}},\qquad k=1,2,\ldots ,m-1}$

${\displaystyle \sum _{r=1}^{m-1}\psi \left({\frac {r}{m}}\right)\cdot \cot {\frac {\pi r}{m}}=-{\frac {\pi (m-1)(m-2)}{6}}}$

${\displaystyle \sum _{r=1}^{m-1}\psi \left({\frac {r}{m}}\right)\cdot {\frac {r}{m}}=-{\frac {\gamma }{2}}(m-1)-{\frac {m}{2}}\ln m-{\frac {\pi }{2}}\sum _{r=1}^{m-1}{\frac {r}{m}}\cdot \cot {\frac {\pi r}{m}}}$

${\displaystyle \sum _{r=1}^{m-1}\psi \left({\frac {r}{m}}\right)\cdot \cos {\dfrac {(2\ell +1)\pi r}{m}}=-{\frac {\pi }{m}}\sum _{r=1}^{m-1}{\frac {r\cdot \sin {\dfrac {2\pi r}{m}}}{\cos {\dfrac {2\pi r}{m}}-\cos {\dfrac {(2\ell +1)\pi }{m}}}},\qquad \ell \in \mathbb {Z} }$

${\displaystyle \sum _{r=1}^{m-1}\psi \left({\frac {r}{m}}\right)\cdot \sin {\dfrac {(2\ell +1)\pi r}{m}}=-(\gamma +\ln 2m)\cot {\frac {(2\ell +1)\pi }{2m}}+\sin {\dfrac {(2\ell +1)\pi }{m}}\sum _{r=1}^{m-1}{\frac {\ln \sin {\dfrac {\pi r}{m}}}{\cos {\dfrac {2\pi r}{m}}-\cos {\dfrac {(2\ell +1)\pi }{m}}}},\qquad \ell \in \mathbb {Z} }$

${\displaystyle \sum _{r=1}^{m-1}\psi ^{2}\left({\frac {r}{m}}\right)=(m-1)\gamma ^{2}+m(2\gamma +\ln 4m)\ln {m}-m(m-1)\ln ^{2}2+{\frac {\pi ^{2}(m^{2}-3m+2)}{12}}+m\sum _{\ell =1}^{m-1}\ln ^{2}\sin {\frac {\pi \ell }{m}}}$

are due to works of certain modern authors (see e.g. Appendix B in Blagouchine (2014)^[17]).

We also have ^[18]

${\displaystyle 1+{\frac {1}{2}}+{\frac {1}{3}}+...+{\frac {1}{k-1}}-\gamma ={\frac {1}{k}}\sum _{n=0}^{k-1}\psi \left(1+{\frac {n}{k}}\right),k=2,3,...}$

Gauss's digamma theorem

For positive integers r and m (r < m), the digamma function may be expressed in terms of Euler's constant and a finite number of elementary functions^[19]

${\displaystyle \psi \left({\frac {r}{m}}\right)=-\gamma -\ln(2m)-{\frac {\pi }{2}}\cot \left({\frac {r\pi }{m}}\right)+2\sum _{n=1}^{\left\lfloor {\frac {m-1}{2}}\right\rfloor }\cos \left({\frac {2\pi nr}{m}}\right)\ln \sin \left({\frac {\pi n}{m}}\right)}$

which holds, because of its recurrence equation, for all rational arguments.

Asymptotic expansion

The digamma function has the asymptotic expansion

${\displaystyle \psi (z)\sim \ln z+\sum _{n=1}^{\infty }{\frac {\zeta (1-n)}{z^{n}}}=\ln z-\sum _{n=1}^{\infty }{\frac {B_{n}}{nz^{n}}},}$

where B_k is the kth Bernoulli number and ζ is the Riemann zeta function. The first few terms of this expansion are:

${\displaystyle \psi (z)\approx \ln z-{\frac {1}{2z}}-{\frac {1}{12z^{2}}}+{\frac {1}{120z^{4}}}-{\frac {1}{252z^{6}}}+{\frac {1}{240z^{8}}}-{\frac {1}{132z^{10}}}+{\frac {691}{32760z^{12}}}-{\frac {1}{12z^{14}}}+\cdots .}$

Although the infinite sum does not converge for any z, any finite partial sum becomes increasingly accurate as z increases.

The expansion can be found by applying the Euler–Maclaurin formula to the sum^[20]

${\displaystyle \sum _{n=1}^{\infty }\left({\frac {1}{n}}-{\frac {1}{z+n}}\right)}$

The expansion can also be derived from the integral representation coming from Binet's second integral formula for the gamma function. Expanding ${\displaystyle t/(t^{2}+z^{2})}$ as a geometric series and substituting an integral representation of the Bernoulli numbers leads to the same asymptotic series as above. Furthermore, expanding only finitely many terms of the series gives a formula with an explicit error term:

${\displaystyle \psi (z)=\ln z-{\frac {1}{2z}}-\sum _{n=1}^{N}{\frac {B_{2n}}{2nz^{2n}}}+(-1)^{N+1}{\frac {2}{z^{2N}}}\int _{0}^{\infty }{\frac {t^{2N+1}\,dt}{(t^{2}+z^{2})(e^{2\pi t}-1)}}.}$

Inequalities

When x > 0, the function

${\displaystyle \ln x-{\frac {1}{2x}}-\psi (x)}$

is completely monotonic and in particular positive. This is a consequence of Bernstein's theorem on monotone functions applied to the integral representation coming from Binet's first integral for the gamma function. Additionally, by the convexity inequality ${\displaystyle 1+t\leq e^{t}}$, the integrand in this representation is bounded above by ${\displaystyle e^{-tz}/2}$. Consequently

${\displaystyle {\frac {1}{x}}-\ln x+\psi (x)}$

is also completely monotonic. It follows that, for all x > 0,

${\displaystyle \ln x-{\frac {1}{x}}\leq \psi (x)\leq \ln x-{\frac {1}{2x}}.}$

This recovers a theorem of Horst Alzer.^[21] Alzer also proved that, for s ∈ (0, 1),

${\displaystyle {\frac {1-s}{x+s}}<\psi (x+1)-\psi (x+s),}$

Related bounds were obtained by Elezovic, Giordano, and Pecaric, who proved that, for x > 0 ,

${\displaystyle \ln(x+{\tfrac {1}{2}})-{\frac {1}{x}}<\psi (x)<\ln(x+e^{-\gamma })-{\frac {1}{x}},}$

where ${\displaystyle \gamma =-\psi (1)}$ is the Euler–Mascheroni constant.^[22] The constants (${\displaystyle 0.5}$ and ${\displaystyle e^{-\gamma }\approx 0.56}$) appearing in these bounds are the best possible.^[23]

The mean value theorem implies the following analog of Gautschi's inequality: If x > c, where c ≈ 1.461 is the unique positive real root of the digamma function, and if s > 0, then

${\displaystyle \exp \left((1-s){\frac {\psi '(x+1)}{\psi (x+1)}}\right)\leq {\frac {\psi (x+1)}{\psi (x+s)}}\leq \exp \left((1-s){\frac {\psi '(x+s)}{\psi (x+s)}}\right).}$

Moreover, equality holds if and only if s = 1.^[24]

Inspired by the harmonic mean value inequality for the classical gamma function, Horzt Alzer and Graham Jameson proved, among other things, a harmonic mean-value inequality for the digamma function:

${\displaystyle -\gamma \leq {\frac {2\psi (x)\psi ({\frac {1}{x}})}{\psi (x)+\psi ({\frac {1}{x}})}}}$ for ${\displaystyle x>0}$

Equality holds if and only if ${\displaystyle x=1}$.^[25]

Computation and approximation

The asymptotic expansion gives an easy way to compute ψ(x) when the real part of x is large. To compute ψ(x) for small x, the recurrence relation

${\displaystyle \psi (x+1)={\frac {1}{x}}+\psi (x)}$

can be used to shift the value of x to a higher value. Beal^[26] suggests using the above recurrence to shift x to a value greater than 6 and then applying the above expansion with terms above x¹⁴ cut off, which yields "more than enough precision" (at least 12 digits except near the zeroes).

As x goes to infinity, ψ(x) gets arbitrarily close to both ln(x − 1/2) and ln x. Going down from x + 1 to x, ψ decreases by 1 / x, ln(x − 1/2) decreases by ln (x + 1/2) / (x − 1/2), which is more than 1 / x, and ln x decreases by ln (1 + 1 / x), which is less than 1 / x. From this we see that for any positive x greater than 1/2,

${\displaystyle \psi (x)\in \left(\ln \left(x-{\tfrac {1}{2}}\right),\ln x\right)}$

or, for any positive x,

${\displaystyle \exp \psi (x)\in \left(x-{\tfrac {1}{2}},x\right).}$

The exponential exp ψ(x) is approximately x − 1/2 for large x, but gets closer to x at small x, approaching 0 at x = 0.

For x < 1, we can calculate limits based on the fact that between 1 and 2, ψ(x) ∈ [−γ, 1 − γ], so

${\displaystyle \psi (x)\in \left(-{\frac {1}{x}}-\gamma ,1-{\frac {1}{x}}-\gamma \right),\quad x\in (0,1)}$

or

${\displaystyle \exp \psi (x)\in \left(\exp \left(-{\frac {1}{x}}-\gamma \right),e\exp \left(-{\frac {1}{x}}-\gamma \right)\right).}$

From the above asymptotic series for ψ, one can derive an asymptotic series for exp(−ψ(x)). The series matches the overall behaviour well, that is, it behaves asymptotically as it should for large arguments, and has a zero of unbounded multiplicity at the origin too.

${\displaystyle {\frac {1}{\exp \psi (x)}}\sim {\frac {1}{x}}+{\frac {1}{2\cdot x^{2}}}+{\frac {5}{4\cdot 3!\cdot x^{3}}}+{\frac {3}{2\cdot 4!\cdot x^{4}}}+{\frac {47}{48\cdot 5!\cdot x^{5}}}-{\frac {5}{16\cdot 6!\cdot x^{6}}}+\cdots }$

This is similar to a Taylor expansion of exp(−ψ(1 / y)) at y = 0, but it does not converge.^[27] (The function is not analytic at infinity.) A similar series exists for exp(ψ(x)) which starts with ${\displaystyle \exp \psi (x)\sim x-{\frac {1}{2}}.}$

If one calculates the asymptotic series for ψ(x+1/2) it turns out that there are no odd powers of x (there is no x⁻¹ term). This leads to the following asymptotic expansion, which saves computing terms of even order.

${\displaystyle \exp \psi \left(x+{\tfrac {1}{2}}\right)\sim x+{\frac {1}{4!\cdot x}}-{\frac {37}{8\cdot 6!\cdot x^{3}}}+{\frac {10313}{72\cdot 8!\cdot x^{5}}}-{\frac {5509121}{384\cdot 10!\cdot x^{7}}}+\cdots }$

Special values

The digamma function has values in closed form for rational numbers, as a result of Gauss's digamma theorem. Some are listed below:

${\displaystyle {\begin{aligned}\psi (1)&=-\gamma \\\psi \left({\tfrac {1}{2}}\right)&=-2\ln {2}-\gamma \\\psi \left({\tfrac {1}{3}}\right)&=-{\frac {\pi }{2{\sqrt {3}}}}-{\frac {3\ln {3}}{2}}-\gamma \\\psi \left({\tfrac {1}{4}}\right)&=-{\frac {\pi }{2}}-3\ln {2}-\gamma \\\psi \left({\tfrac {1}{6}}\right)&=-{\frac {\pi {\sqrt {3}}}{2}}-2\ln {2}-{\frac {3\ln {3}}{2}}-\gamma \\\psi \left({\tfrac {1}{8}}\right)&=-{\frac {\pi }{2}}-4\ln {2}-{\frac {\pi +\ln \left({\sqrt {2}}+1\right)-\ln \left({\sqrt {2}}-1\right)}{\sqrt {2}}}-\gamma .\end{aligned}}}$

Moreover, by taking the logarithmic derivative of ${\displaystyle |\Gamma (bi)|^{2}}$ or ${\displaystyle |\Gamma ({\tfrac {1}{2}}+bi)|^{2}}$ where ${\displaystyle b}$ is real-valued, it can easily be deduced that

${\displaystyle \operatorname {Im} \psi (bi)={\frac {1}{2b}}+{\frac {\pi }{2}}\coth(\pi b),}$

${\displaystyle \operatorname {Im} \psi ({\tfrac {1}{2}}+bi)={\frac {\pi }{2}}\tanh(\pi b).}$

Apart from Gauss's digamma theorem, no such closed formula is known for the real part in general. We have, for example, at the imaginary unit the numerical approximation

${\displaystyle \operatorname {Re} \psi (i)=-\gamma -\sum _{n=0}^{\infty }{\frac {n-1}{n^{3}+n^{2}+n+1}}\approx 0.09465.}$

Roots of the digamma function

The roots of the digamma function are the saddle points of the complex-valued gamma function. Thus they lie all on the real axis. The only one on the positive real axis is the unique minimum of the real-valued gamma function on R⁺ at x₀ = 1.46163214496836234126.... All others occur single between the poles on the negative axis:

x₁ = −0.50408300826445540925...

x₂ = −1.57349847316239045877...

x₃ = −2.61072086844414465000...

x₄ = −3.63529336643690109783...

${\displaystyle \vdots }$

Already in 1881, Charles Hermite observed^[28] that

${\displaystyle x_{n}=-n+{\frac {1}{\ln n}}+O\left({\frac {1}{(\ln n)^{2}}}\right)}$

holds asymptotically. A better approximation of the location of the roots is given by

${\displaystyle x_{n}\approx -n+{\frac {1}{\pi }}\arctan \left({\frac {\pi }{\ln n}}\right)\qquad n\geq 2}$

and using a further term it becomes still better

${\displaystyle x_{n}\approx -n+{\frac {1}{\pi }}\arctan \left({\frac {\pi }{\ln n+{\frac {1}{8n}}}}\right)\qquad n\geq 1}$

which both spring off the reflection formula via

${\displaystyle 0=\psi (1-x_{n})=\psi (x_{n})+{\frac {\pi }{\tan \pi x_{n}}}}$

and substituting ψ(x_n) by its not convergent asymptotic expansion. The correct second term of this expansion is 1 / 2n, where the given one works well to approximate roots with small n.

Another improvement of Hermite's formula can be given:^[11]

${\displaystyle x_{n}=-n+{\frac {1}{\log n}}-{\frac {1}{2n(\log n)^{2}}}+O\left({\frac {1}{n^{2}(\log n)^{2}}}\right).}$

Regarding the zeros, the following infinite sum identities were recently proved by István Mező and Michael Hoffman^[11][29]

${\displaystyle {\begin{aligned}\sum _{n=0}^{\infty }{\frac {1}{x_{n}^{2}}}&=\gamma ^{2}+{\frac {\pi ^{2}}{2}},\\\sum _{n=0}^{\infty }{\frac {1}{x_{n}^{3}}}&=-4\zeta (3)-\gamma ^{3}-{\frac {\gamma \pi ^{2}}{2}},\\\sum _{n=0}^{\infty }{\frac {1}{x_{n}^{4}}}&=\gamma ^{4}+{\frac {\pi ^{4}}{9}}+{\frac {2}{3}}\gamma ^{2}\pi ^{2}+4\gamma \zeta (3).\end{aligned}}}$

In general, the function

${\displaystyle Z(k)=\sum _{n=0}^{\infty }{\frac {1}{x_{n}^{k}}}}$

can be determined and it is studied in detail by the cited authors.

The following results^[11]

${\displaystyle {\begin{aligned}\sum _{n=0}^{\infty }{\frac {1}{x_{n}^{2}+x_{n}}}&=-2,\\\sum _{n=0}^{\infty }{\frac {1}{x_{n}^{2}-x_{n}}}&=\gamma +{\frac {\pi ^{2}}{6\gamma }}\end{aligned}}}$

also hold true.

Regularization

The digamma function appears in the regularization of divergent integrals

${\displaystyle \int _{0}^{\infty }{\frac {dx}{x+a}},}$

this integral can be approximated by a divergent general Harmonic series, but the following value can be attached to the series

${\displaystyle \sum _{n=0}^{\infty }{\frac {1}{n+a}}=-\psi (a).}$

See also

• Polygamma function
• Trigamma function
• Chebyshev expansions of the digamma function in Wimp, Jet (1961). "Polynomial approximations to integral transforms". Math. Comp. 15 (74): 174–178. doi:10.1090/S0025-5718-61-99221-3.

References

External links

• OEIS sequence A020759 (Decimal expansion of (-1)*Gamma'(1/2)/Gamma(1/2) where Gamma(x) denotes the Gamma function)—psi(1/2)

OEIS: A047787 psi(1/3), OEIS: A200064 psi(2/3), OEIS: A020777 psi(1/4), OEIS: A200134 psi(3/4), OEIS: A200135 to OEIS: A200138 psi(1/5) to psi(4/5).