Q查理耶多项式

令Q查理耶多项式 a→a*(1-q),并令q→1，即得查理耶多项式

${\displaystyle lim_{q\to 1}C_{n}(q^{-n};a(1-q);q)=C_{n}(x;a)}$

验证Q查理耶多项式→查理耶多项式

Q查理耶多项式之第4项(k=4):

${\displaystyle {\frac {\left(1-{q}^{-n}\right)\left(1-{q}^{-n}q\right)\left(1-{q}^{-n}{q}^{2}\right)\left(1-{q}^{-n}{q}^{3}\right)\left(1-{q}^{-x}\right)\left(1-{q}^{-x}q\right)\left(1-{q}^{-x}{q}^{2}\right)\left(1-{q}^{-x}{q}^{3}\right)\left({q}^{n}\right)^{4}{q}^{4}}{{a}^{4}\left(1-q\right)^{5}\left(1-{q}^{2}\right)\left(1-{q}^{3}\right)\left(1-{q}^{4}\right)}}}$ 展开之： ${\displaystyle {\frac {1}{24}}\,{\frac {36\,nx-66\,n{x}^{2}+36\,n{x}^{3}-6\,n{x}^{4}-66\,{n}^{2}x+121\,{n}^{2}{x}^{2}-66\,{n}^{2}{x}^{3}+11\,{n}^{2}{x}^{4}+36\,{n}^{3}x-66\,{n}^{3}{x}^{2}+36\,{n}^{3}{x}^{3}-6\,{n}^{3}{x}^{4}-6\,{n}^{4}x+11\,{n}^{4}{x}^{2}-6\,{n}^{4}{x}^{3}+{n}^{4}{x}^{4}}{{a}^{4}}}}$

另一方面 查理耶多项式的k=4项为

${\displaystyle {\frac {1}{24}}\,{\frac {{\it {pochhammer}}\left(-n,4\right){\it {pochhammer}}\left(-x,4\right)}{{a}^{4}}}}$

展开之

${\displaystyle {\frac {1}{24}}\,{\frac {nx\left(36-66\,x+36\,{x}^{2}-6\,{x}^{3}-66\,n+121\,nx-66\,n{x}^{2}+11\,n{x}^{3}+36\,{n}^{2}-66\,{n}^{2}x+36\,{n}^{2}{x}^{2}-6\,{n}^{2}{x}^{3}-6\,{n}^{3}+11\,{n}^{3}x-6\,{n}^{3}{x}^{2}+{n}^{3}{x}^{3}\right)}{{a}^{4}}}}$

二者显然相等 QED

• Gasper, George; Rahman, Mizan, , Encyclopedia of Mathematics and its Applications 96 2nd, Cambridge University Press, 2004, ISBN 978-0-521-83357-8, MR 2128719, doi:10.2277/0521833574
• Koekoek, Roelof; Lesky, Peter A.; Swarttouw, René F., , Springer Monographs in Mathematics, Berlin, New York: Springer-Verlag, 2010, ISBN 978-3-642-05013-8, MR 2656096, doi:10.1007/978-3-642-05014-5
• Koornwinder, Tom H.; Wong, Roderick S. C.; Koekoek, Roelof; Swarttouw, René F., http://dlmf.nist.gov/18 |contribution-url=缺少标题 (帮助), Olver, Frank W. J.; Lozier, Daniel M.; Boisvert, Ronald F.; Clark, Charles W. (编), , Cambridge University Press, 2010, ISBN 978-0521192255, MR2723248