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Elections in Georgia |
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The 1819 Georgia gubernatorial election was held on 5 November 1819 in order to elect the Governor of Georgia. Democratic-Republican candidate John Clark defeated fellow Democratic-Republican candidate and former United States Senator for Georgia George Troup in a Georgia General Assembly vote.[1]
General election
On election day, 5 November 1819, Democratic-Republican candidate John Clark won the election against his opponent fellow Democratic-Republican candidate George Troup. Clark was sworn in as the 31st Governor of Georgia on 5 November 1819.[2]
Results
Party | Candidate | Votes | % | |
---|---|---|---|---|
Democratic-Republican | John Clark | 73 | 54.89 | |
Democratic-Republican | George Troup | 60 | 45.11 | |
Total votes | 133 | 100.00 | ||
Democratic-Republican hold | ||||
References
- ↑ "Georgia 1819 Governor". Tufts Digital Collations and Archives. A New Nation Votes: American Election Returns 1787–1825. Tufts University. Retrieved 8 December 2023.
- ↑ "GA Governor". ourcampaigns.com. 18 July 2022. Retrieved 8 December 2023.
- ↑ Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. ISBN 9780786414390.
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