1890 Wisconsin gubernatorial election
November 4, 1890
 
Nominee George Wilbur Peck William D. Hoard
Party Democratic Republican
Popular vote 160,388 132,068
Percentage 51.86% 42.70%
County results
Peck :      40-50%      50–60%      60–70%      70–80%      80-90%
Hoard :      40–50%      50–60%      60–70%
Governor before election

William D. Hoard
Republican

 Elected Governor

George Wilbur Peck
Democratic

The 1890 Wisconsin gubernatorial election was held on November 4, 1890.

Incumbent Republican Governor William D. Hoard was defeated by Democratic nominee George Wilbur Peck.

Peck became the first Democratic Governor of Wisconsin since William Robert Taylor in 1876.

General election

Candidates

Major party candidates

Other candidates

Results

1890 Wisconsin gubernatorial election[1][2][3][4]
Party Candidate Votes % ±%
Democratic George Wilbur Peck 160,388 51.86%
Republican William D. Hoard (incumbent) 132,068 42.70%
Prohibition Charles Alexander 11,246 3.64%
Labor Reuben May 5,447 1.76%
Scattering 105 0.03%
Majority 28,320 9.16%
Turnout 309,254 100.00%
Democratic gain from Republican Swing

References

  1. ↑ Congressional Quarterly 1998, p. 87.
  2. ↑ "WI Governor, 1890". Our Campaigns. Retrieved July 10, 2021.
  3. ↑ Wisconsin Blue Book 1891, pp. 256–257.
  4. ↑ Glashan 1979, pp. 340–341.

Bibliography

  • Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Meckler Books. ISBN 0-930466-17-9.
  • Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
  • Cunningham, Thomas J., ed. (1891). The Blue Book of the State of Wisconsin. The Milwaukee Litho. & Engr. Co.
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