Singles
1991 Arizona Classic
Champion	Sabine Appelmans
Runner-up	Chanda Rubin
Score	7–5, 6–1
Draw	32 (4Q)
Seeds	8

Conchita Martínez was the defending champion, but did not compete this year.

Sabine Appelmans won the title by defeating Chanda Rubin 7–5, 6–1 in the final.^[1]

Seeds

Draw

Finals

	Semifinals							Final
	Q	Chanda Rubin	6	6
		Karina Habšudová	2	4
								Q	Chanda Rubin	5	1
								3	Sabine Appelmans	7	6
	3	Sabine Appelmans	3	6	6
	2	Julie Halard	6	3	3

Top half

	First round							Second round							Quarterfinals							Semifinals
	1	G Fernández	6	6
		E Reinach	2	2				1	G Fernández	4	2
		S Hack	0	2					G Helgeson	6	6
		G Helgeson	6	6												G Helgeson	3	5
	Q	C Rubin	6	6											Q	C Rubin	6	7
		E Smylie	3	0				Q	C Rubin	62	6	6
		P Harper	65	6	6				P Harper	77	0	3
	6	Y Basuki	77	3	2																	Q	C Rubin	6	6
	4	A Frazier	6	6																			K Habšudová	2	4
		F Labat	3	1				4	A Frazier	3	66
		K Habšudová	6	7					K Habšudová	6	78
	Q	J Emmons	1	5												K Habšudová	4	6	6
	Q	K Po	3	7	6										Q	K Po	6	1	3
		I Demongeot	6	5	3			Q	K Po	6	1	6
		T Whitlinger	6	4	7				T Whitlinger	1	6	2
	8	D Graham	3	6	5

Bottom half

	First round							Second round							Quarterfinals							Semifinals
	7	B Rittner	5	3
		N Provis	7	6					N Provis	78	6
	Q	R White	6	6				Q	R White	66	1
		V Martinek	3	2												N Provis	65	4
		L Harvey Wild	2	4											3	S Appelmans	77	6
		C Cunningham	6	6					C Cunningham	5	0
		A Gavaldón	5	3				3	S Appelmans	7	6
	3	S Appelmans	7	6																		3	S Appelmans	3	6	6
	5	M Werdel	6	4	4																	2	J Halard	6	3	3
		P Ritter	2	6	6				P Ritter	65	1
		C Tessi	6	4	4				P Fendick	77	6
		P Fendick	3	6	6											P Fendick	6	4	1
		A Grossman	6	6											2	J Halard	4	6	6
		A May	1	3					A Grossman	6	4	4
		S Stafford	2	6	4			2	J Halard	3	6	6
	2	J Halard	6	3	6

References

External links

• Official results archive (ITF)
• Official results archive (WTA)