Doubles
1999 Mercedes-Benz Cup
Champions	Byron Black Wayne Ferreira
Runners-up	Goran Ivanišević Brian MacPhie
Score	6–2, 7–6(7–4)
Draw	16
Seeds	4

Patrick Rafter and Sandon Stolle were the defending champions, but Rafter did not compete this year. Stolle teamed up with Wayne Black and lost in the semifinals to Byron Black and Wayne Ferreira.

Byron Black and Ferreira won the title by defeating Goran Ivanišević and Brian MacPhie 6–2, 7–6^(7–4) in the final.^[1][2]

Seeds

Draw

Draw

	First round							Quarterfinals							Semifinals							Final
	1	J Björkman L Paes	6	6
		A Florent P Kilderry	2	3				1	J Björkman L Paes	3	6	3
		M Barnard B Haygarth	3	1					M Damm A Peterson	6	3	6
		M Damm A Peterson	6	6												M Damm A Peterson	3	5
	4	J Gimelstob S Humphries	6	65	6											G Ivanišević B MacPhie	6	7
		G Grant M Tebbutt	3	77	4			4	J Gimelstob S Humphries	77	4	2
	WC	JM Gambill R Leach	3	4					G Ivanišević B MacPhie	61	6	6
		G Ivanišević B MacPhie	6	6																			G Ivanišević B MacPhie	2	64
		B Black W Ferreira	6	6																			B Black W Ferreira	6	77
	WC	P Annacone P Sampras	4	2					B Black W Ferreira	77	6
	WC	T Enqvist M Larsson	3	6	2			3	JL de Jager J Grabb	64	1
	3	JL de Jager J Grabb	6	4	6											B Black W Ferreira	6	6
		B Coupe E Taino	2	4											2	W Black S Stolle	4	2
		L Hewitt M Woodforde	6	6					L Hewitt M Woodforde	6	3	2
	Q	M Joyce K Spencer	2	1				2	W Black S Stolle	3	6	6
	2	W Black S Stolle	6	6

References

External links

• Official results archive (ATP)
• Official results archive (ITF)