Glasgow – Doubles
2019 Murray Trophy – Glasgow
Champions	Ruben Bemelmans Daniel Masur
Runners-up	Jamie Murray John-Patrick Smith
Score	4–6, 6–3, [10–8]

Gerard Granollers and Guillermo Olaso were the defending champions^[1] but chose not to defend their title.

Ruben Bemelmans and Daniel Masur won the title after defeating Jamie Murray and John-Patrick Smith 4–6, 6–3, [10–8] in the final.

Seeds

Draw

Key

• Q = Qualifier
• WC = Wild card
• LL = Lucky loser
• Alt = Alternate
• SE = Special exempt
• PR = Protected ranking
• ITF = ITF entry
• JE = Junior exempt
• w/o = Walkover
• r = Retired
• d = Defaulted
• SR = Special ranking

	First round							Quarterfinals							Semifinals							Final
	1	J Murray J-P Smith	6	6
	WC	Marshall Tutu David Wright	4	2				1	J Murray J-P Smith	6	6
	Alt	A Çelikbilek C İlkel	77	78				Alt	A Çelikbilek C İlkel	3	4
		H Heliövaara E Ruusuvuori	65	66											1	J Murray J-P Smith	6	6
	4	K Drzewiecki S Walków	3	6	[10]											M Gengel R Ramanathan	2	3
	WC	L Johnson Mark Whitehouse	6	3	[3]			4	K Drzewiecki S Walków	4	6	[3]
		M Gengel R Ramanathan	7	79					M Gengel R Ramanathan	6	3	[10]
		S Clayton L Glasspool	5	67																		1	J Murray J-P Smith	6	3	[8]
		N Kuhn J Rodionov	w/o																				R Bemelmans D Masur	4	6	[10]
		G Blancaneaux A Rinderknech							N Kuhn J Rodionov
		R Bemelmans D Masur	77	6					R Bemelmans D Masur	w/o
	3	A Göransson S Verbeek	62	4												R Bemelmans D Masur	6	4	[11]
		J Ocleppo R Ortega Olmedo	64	5											2	N Lammons A Šančić	4	6	[9]
		Q Halys M Martineau	77	7					Q Halys M Martineau	4	2
		R Gonzales A Siljeström	4	63				2	N Lammons A Šančić	6	6
	2	N Lammons A Šančić	6	77

References

• Main draw