| Doubles | |
|---|---|
| 2020 Bangkok Challenger | |
| Champions | |
| Runners-up | |
| Score | 3–6, 7–6(7–1), [10–5] |
Gong Maoxin and Zhang Ze were the defending champions[1] but lost in the first round to Treat Huey and Nathaniel Lammons.
Andrey Golubev and Aleksandr Nedovyesov won the title after defeating Sanchai Ratiwatana and Christopher Rungkat 3–6, 7–6(7–1), [10–5] in the final.
Seeds
Gonzalo Escobar /
Miguel Ángel Reyes-Varela (semifinals)
Romain Arneodo /
Andre Begemann (quarterfinals)
Tomislav Brkić /
Ante Pavić (first round)
Purav Raja /
Adil Shamasdin (first round)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
| First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
| 1 | 7 | 7 | |||||||||||||||||||||||||
| 5 | 5 | 1 | 6 | 6 | |||||||||||||||||||||||
| 6 | 6 | 4 | 4 | ||||||||||||||||||||||||
| 3 | 4 | 1 | 63 | 3 | |||||||||||||||||||||||
| 4 | 65 | 6 | [6] | WC | 77 | 6 | |||||||||||||||||||||
| 77 | 3 | [10] | 5 | 1 | |||||||||||||||||||||||
| WC | 6 | 3 | [10] | WC | 7 | 6 | |||||||||||||||||||||
| 2 | 6 | [6] | WC | 3 | 77 | [10] | |||||||||||||||||||||
| 3 | 3 | 6 | 61 | [5] | |||||||||||||||||||||||
| 6 | 6 | 77 | 6 | ||||||||||||||||||||||||
| 6 | 6 | 63 | 1 | ||||||||||||||||||||||||
| 3 | 4 | 4 | 4 | 77 | [7] | ||||||||||||||||||||||
| WC | 4 | 3 | 6 | 62 | [10] | ||||||||||||||||||||||
| 6 | 6 | 6 | 68 | [10] | |||||||||||||||||||||||
| WC | 4 | 4 | 2 | 4 | 710 | [8] | |||||||||||||||||||||
| 2 | 6 | 6 | |||||||||||||||||||||||||
References
- ↑ "Laaksonen Returns To Winners' Circle At Bangkok Open". February 17, 2019.
External links
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