Doubles
2021 Thoreau Tennis Open
Champions	Peangtarn Plipuech Jessy Rompies
Runners-up	Usue Maitane Arconada Cristina Bucșa
Score	3–6, 7–6(7–5), [10–8]

Angela Kulikov and Rianna Valdes were the defending champions, having won the previous edition in 2019^[1] but lost in the quarterfinals to Usue Maitane Arconada and Cristina Bucșa.

Peangtarn Plipuech and Jessy Rompies won the title, defeating Arconada and Bucșa in the final, 3–6, 7–6^(7–5), [10–8].

Seeds

Draw

Draw

	First round							Quarterfinals							Semifinals							Final
	1	S-w Hsieh Y-c Hsieh	6	6
		L Davis C McHale	3	2				1	S-w Hsieh Y-c Hsieh	64	4
		G Voskoboeva V Zvonareva	6	6					G Voskoboeva V Zvonareva	77	6
		L Küng R Zarazúa	1	1												G Voskoboeva V Zvonareva	6	1	[9]
	3	K Bondarenko T Maria	6	6												P Plipuech J Rompies	4	6	[11]
		C-y Hsu R Marino	3	3				3	K Bondarenko T Maria	5	3
		P Plipuech J Rompies	6	6					P Plipuech J Rompies	7	6
	WC	B Collens V Hu	1	0																			P Plipuech J Rompies	3	77	[10]
		A Kulikov R Valdes	6	4	[14]																		UM Arconada C Bucșa	6	65	[8]
		C Harrison S Murray Sharan	2	6	[12]				A Kulikov R Valdes	4	0
		UM Arconada C Bucșa	6	77					UM Arconada C Bucșa	6	6
	4	Q Gleason J Loeb	3	65												UM Arconada C Bucșa	4	6	[10]
		S Chang S Whittle	4	6	[10]										Alt	M Barthel A Raina	6	4	[8]
		R Anderson B Gumulya	6	3	[8]				S Chang S Whittle	5	2
		L Cabrera M Inglis	6	4	[3]			Alt	M Barthel A Raina	7	6
	Alt	M Barthel A Raina	3	6	[10]

References

External links

• Main Draw