1888 Belgian general election

12 June 1888 (1888-06-12)
69 of the 138 seats in the Chamber of Representatives 70 seats needed for a majority
First party Second party   Leader Auguste Beernaert Party Catholic Liberal Leader since Candidate for PM Seats before 98 seats 40 seats Seats won 66 3 Seats after 98 40 Seat change Popular vote 31,273 19,967 Percentage 58.44% 37.31%
Government before election Beernaert Catholic Government after election Beernaert Catholic

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Partial general elections were held in Belgium on 12 June 1888.^[1][2] The result was a victory for the Catholic Party, which won 98 of the 138 seats in the Chamber of Representatives and 47 of the 69 seats in the Senate.^[2]

Under the alternating system, elections were held in only five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders.

Results

Chamber of Representatives

Party		Votes	%	Seats
				Won	Total	+/–
	Catholic Party	31,273	58.44	66	98	0
	Liberal Party	19,967	37.31	3	40	0
	Others	2,277	4.25	0	0	New
Total		53,517	100.00	69	138	0
Total votes		53,517	–
Registered voters/turnout		73,276	73.03
Source: Mackie & Rose,[3] Sternberger et al.

Senate

Party		Seats
	Catholic Party	47
	Liberal Party	18
	Independents	4
Total		69
Source: Sternberger et al.

References