Indian Grove Township
Township
Location in Livingston County
Location in Livingston County
Livingston County's location in Illinois
Livingston County's location in Illinois
CountryUnited States
StateIllinois
CountyLivingston
EstablishedNovember 3, 1857
Area
 • Total36.33 sq mi (94.1 km2)
 • Land36.1 sq mi (93 km2)
 • Water0.23 sq mi (0.6 km2)  0.63%
Population
 (2010)
 • Estimate 
(2016)[1]
4,104
 • Density119/sq mi (46/km2)
Time zoneUTC-6 (CST)
 • Summer (DST)UTC-5 (CDT)
FIPS code17-105-37244

Indian Grove Township is located in Livingston County, Illinois. As of the 2010 census, its population was 4,297 and it contained 1,814 housing units.[2] Indian Grove Township changed its name from Worth Township on May 11, 1858.

Geography

According to the 2010 census, the township has a total area of 36.33 square miles (94.1 km2), of which 36.1 square miles (93 km2) (or 99.37%) is land and 0.23 square miles (0.60 km2) (or 0.63%) is water.[2]

Demographics

Historical population
CensusPop.Note%±
2016 (est.)4,104[1]
U.S. Decennial Census[3]

References

  1. 1 2 "Population and Housing Unit Estimates". Retrieved June 9, 2017.
  2. 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 28, 2013.
  3. ↑ "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.

40°43′02″N 88°31′45″W / 40.71722°N 88.52917°W / 40.71722; -88.52917


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