1912 Vermont gubernatorial election
September 3, 1912 (1912-09-03)
 
Candidate Allen M. Fletcher Harland B. Howe Fraser Metzger
Party Republican Democratic Progressive
Popular vote 26,237 20,001 15,629
Percentage 40.5% 30.8% 24.1%
Governor before election

John A. Mead
Republican

 Elected Governor

Allen M. Fletcher
Republican

The 1912 Vermont gubernatorial election took place on September 3, 1912. Incumbent Republican John A. Mead, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate Allen M. Fletcher defeated Democratic candidate Harland B. Howe and Progressive candidate Fraser Metzger to succeed him. Since no candidate won a majority of the popular vote, the election was decided and Fletcher was elected by the Vermont General Assembly in accordance with the state constitution.[2]

This was the last time until 1986 that none of the gubernatorial candidates received a majority of the vote.[3]

Results

1912 Vermont gubernatorial election[2]
Party Candidate Votes % ±%
Republican Allen M. Fletcher 26,237 40.5
Democratic Harland B. Howe 20,001 30.8
Progressive Fraser Metzger 15,629 24.1
Prohibition Clement F. Smith 1,735 2.7
Socialist Fred W. Suitor 1,210 1.9
N/A Other 27 0.0
Total votes '64,839' '100'

References

  1. ↑ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved January 1, 2015.
  2. 1 2 "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Archived from the original (PDF) on November 30, 2014. Retrieved January 1, 2015.
  3. ↑ Doyle 1992, p. 222.

Works cited


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