英語
詞源
發音
- (美國) 國際音標(幫助):/ˈæb.ɹəˌɡeɪ.tɚ/
名詞
(複數)
參考資料
- ↑ Lesley Brown, editor-in-chief; William R. Trumble and Angus Stevenson, editors (2002), “abrogator”, The Shorter Oxford English Dictionary on Historical Principles, 5th版, Oxford; New York, N.Y.: Oxford University Press, ISBN 978-0-19-860457-0, 页8
- “abrogator”, Webster’s Revised Unabridged Dictionary, Springfield, Mass.: G. & C. Merriam, 1913, OCLC 800618302
拉丁語
動詞
參考資料
- abrogator in Ramminger, Johann (访问于16 July 2016) Neulateinische Wortliste: Ein Wörterbuch des Lateinischen von Petrarca bis 1700, pre-publication website, 2005-2016
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