1828 United States presidential election in Ohio
October 31 – December 2, 1828
 
Nominee Andrew Jackson John Quincy Adams
Party Democratic National Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun Richard Rush
Electoral vote 16 0
Popular vote 67,595 63,394
Percentage 51.60% 48.40%
County Results
President before election

John Quincy Adams
Democratic-Republican

 Elected President

Andrew Jackson
Democratic

The 1828 United States presidential election in Ohio took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 16 representatives, or electors to the Electoral College, who voted for President and Vice President.

Ohio voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Ohio by a narrow margin of 3.2%. This was the first election of the Second Party System, and as such the first election in which Ohio voted for a candidate of a party other than the Democratic-Republicans.

Results

1828 United States presidential election in Ohio[1]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson 67,597 51.60% 16
National Republican John Quincy Adams (incumbent) 63,396 48.40% 0
Totals 130,993 100.0% 16

See also

References

  1. ↑ "1828 Presidential General Election Results - Ohio". U.S. Election Atlas. Retrieved February 28, 2013.
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