1832 United States presidential election in Indiana
November 2 – December 5, 1832
 
Nominee Andrew Jackson Henry Clay
Party Democratic National Republican
Home state Tennessee Kentucky
Running mate Martin Van Buren John Sergeant
Electoral vote 9 0
Popular vote 31,551 15,472
Percentage 67.10% 32.90%

The 1832 United States presidential election in Indiana took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

Indiana voted for the Democratic Party candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Indiana by a margin of 34.20%.

As of 2020, this remains the strongest performance by a Democrat in Indiana.[1]

Results

1832 United States presidential election in Indiana[2]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson (incumbent) 31,551 67.10% 9
National Republican Henry Clay 15,472 32.90% 0
Totals 47,023 100.0% 9

See also

References

  1. ↑ "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved January 10, 2023.
  2. ↑ "1832 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved April 12, 2013.
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