1868 United States presidential election in Oregon
November 3, 1868
 
Nominee Horatio Seymour Ulysses S. Grant
Party Democratic Republican
Home state New York Illinois
Running mate Francis Preston Blair, Jr. Schuyler Colfax
Electoral vote 3 0
Popular vote 11,125 10,961
Percentage 50.37% 49.63%
County Results
President before election

Andrew Johnson
Democratic

 Elected President

Ulysses S. Grant
Republican

The 1868 United States presidential election in Oregon took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Oregon voted for the Democratic nominee, Horatio Seymour over the Republican nominee, Ulysses S. Grant. Seymour won the state by a narrow margin of 0.74%.

As a result of his win, Seymour became the first Democratic presidential candidate to ever win Oregon. Another Democrat would not win Oregon again on a presidential level until Woodrow Wilson won the state in 1912.

This was the only time a Republican would win a presidential election without Oregon until 1988, 120 years later; every Republican victor since then has lost the state.

Results

1868 United States presidential election in Oregon[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Horatio Seymour of New York Francis Preston Blair, Jr. of Missouri 11,125 50.37% 3 100.00%
Republican Ulysses S. Grant of Illinois Schuyler Colfax of Indiana 10,961 49.63% 0 0.00%
Total 22,086 100.00% 3 100.00%

See also

References

  1. ↑ "1868 Presidential General Election Results - Oregon".


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