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County Results
Clinton 50–60% 60–70%
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Elections in Hawaii |
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The 1996 United States presidential election in Hawaii took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College, who voted for president and vice president.
Hawaii was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 56.93% to 31.64% by a margin of 25.29%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third, with 7.6% of the popular vote.[1]
Results
1996 United States presidential election in Hawaii | ||||||
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Party | Candidate | Running mate | Votes | Percentage | Electoral votes | |
Democratic | Bill Clinton (incumbent) | Al Gore | 205,012 | 56.93% | 4 | |
Republican | Bob Dole | Jack Kemp | 113,943 | 31.64% | 0 | |
Reform | Ross Perot | Pat Choate | 27,358 | 7.60% | 0 | |
Green | Ralph Nader | Winona LaDuke | 10,386 | 2.88% | 0 | |
Libertarian | Harry Browne | Jo Jorgensen | 2,493 | 0.69% | 0 | |
Natural Law | Dr. John Hagelin | Dr. V. Tompkins | 570 | 0.16% | 0 | |
U.S. Taxpayers' Party | Howard Phillips | Herbert Titus | 358 | 0.10% | 0 | |
Totals | 360,120 | 100.0% | 4 |
By county
County | Clinton | Votes | Dole | Votes | Others | Votes |
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Hawaii | 55.6% | 27,262 | 27.6% | 13,516 | 16.7% | 8,199 |
Honolulu | 56.3% | 143,793 | 33.6% | 85,779 | 10.0% | 25,684 |
Kalawao | 73.0% | 46 | 20.6% | 13 | 6.3% | 4 |
Kauai | 63.5% | 13,357 | 25.3% | 5,325 | 11.1% | 2,338 |
Maui | 59.0% | 20,600 | 26.7% | 9,323 | 14.1% | 4,944 |
References
- ↑ Leip, David. "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved June 14, 2018.
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