Oak Grove Township
Location of Oak Grove Township in Benton County
Location of Oak Grove Township in Benton County
Coordinates: 40°31′09″N 87°15′54″W / 40.51917°N 87.26500°W / 40.51917; -87.26500
CountryUnited States
StateIndiana
CountyBenton
OrganizedJuly 1840
Government
  TypeIndiana township
Area
  Total35.53 sq mi (92.0 km2)
  Land35.51 sq mi (92.0 km2)
  Water0.02 sq mi (0.05 km2)
Elevation748 ft (228 m)
Population
 (2020)
  Total1,551
  Density43.6/sq mi (16.8/km2)
Time zoneUTC-5 (EST)
  Summer (DST)UTC-4 (EDT)
FIPS code18-55620[2]
GNIS feature ID453681

Oak Grove Township is one of eleven townships in Benton County, Indiana. As of the 2020 census, its population was 1,551 and it contained 690 housing units.[3] It was one of the first three townships originally created by the county's commissioners in 1840.[4] It takes its name from White Oak Grove which grew southwest of Oxford.[5]

Geography

According to the 2020 census, the township has a total area of 35.53 square miles (92.0 km2), of which 35.51 square miles (92.0 km2) (or 99.94%) is land and 0.02 square miles (0.052 km2) (or 0.06%) is water.[3]

Cities and towns

Unincorporated towns

Adjacent townships

Major highways

Cemeteries

The township contains two cemeteries: Justus and Oxford.

References

Citations

  1. "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
  2. "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
  3. 1 2 "Explore Census Data". US Census Bureau. Retrieved February 18, 2022.
  4. Birch, Jesse Setlington (1942) [1928]. History of Benton County and Historic Oxford. Oxford, Indiana: Craw & Craw, Inc. p. 20.
  5. Andreas, Alfred Theodore (1876). "Benton County". Illustrated Historical Atlas of the State of Indiana. Chicago: Baskin, Forster & Company.

Sources

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.