Oran Township
Township
Location in Fayette County
Location in Fayette County
Coordinates: 42°41′05″N 92°01′27″W / 42.68472°N 92.02417°W / 42.68472; -92.02417
Country United States
State Iowa
CountyFayette
Area
 • Total36.66 sq mi (94.94 km2)
 • Land36.65 sq mi (94.91 km2)
 • Water0.01 sq mi (0.03 km2)  0.03%
Elevation
1,027 ft (313 m)
Population
 (2010)
 • Total760
 • Density21/sq mi (8.0/km2)
Time zoneUTC-6 (CST)
 • Summer (DST)UTC-5 (CDT)
ZIP codes
50629, 50662
GNIS feature ID0468467

Oran Township is one of twenty townships in Fayette County, Iowa, USA. As of the 2010 census, its population was 760.[1]

Geography

According to the United States Census Bureau, Oran Township covers an area of 36.66 square miles (94.94 square kilometers); of this, 36.65 square miles (94.91 square kilometers, 99.97 percent) is land and 0.01 square miles (0.03 square kilometers, 0.03 percent) is water.

Cities, towns, villages

Unincorporated towns

(This list is based on USGS data and may include former settlements.)

Adjacent townships

Cemeteries

The township contains these four cemeteries: Fairbank, Immaculate Conception, Oran Township and Oran Township.

Major highways

Airports and landing strips

  • Oelwein Municipal Airport

School districts

  • Oelwein Community School District
  • Wapsie Valley Community School District
  • West Central Community School District

Political districts

References

  1. ↑ "Profile of General Population and Housing Characteristics: 2010 Demographic Profile Data (DP-1): Oran township, Fayette County, Iowa". United States Census Bureau. Retrieved March 5, 2012.
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