1793 Pennsylvania gubernatorial election

October 8, 1793 (1793-10-08)[1]
 
Candidate Thomas Mifflin Frederick Muhlenberg
Party Democratic-Republican Federalist
Popular vote 20,479 10,803
Percentage 65.4% 34.5%

County Results


Mifflin:      50-60%      60-70%      70-80%      80-90%      90-100%
Muhlenberg:      50-60%

     60-70%

Governor before election

Thomas Mifflin
Democratic-Republican

Elected Governor

Thomas Mifflin
Democratic-Republican

The 1793 Pennsylvania gubernatorial election occurred on October 8, 1793. Incumbent Democratic-Republican governor Thomas Mifflin sought re-election to another term, defeating Federalist candidate and U.S. Representative Frederick Muhlenberg. Muhlenberg won only two counties: York and Bedford. However, Mifflin's 2-1 vote margin was down from his 10-1 victory margin in the 1790 gubernatorial election.[2]

Results

Pennsylvania gubernatorial election, 1793[3][4]
Party Candidate Votes %
Democratic-Republican Thomas Mifflin (incumbent) 20,479 65.43
Federalist Frederick Muhlenberg 10,803 34.51
Independent Alexander McDowell 8 0.03
N/A Others 11 0.04
Total votes 31,301 100.00

References

  1. "Article II". Constitution of the Commonwealth of Pennsylvania - 1790 (PDF).
  2. Tinkcom, Harry Marlin. 1950. The Republicans and Federalists in Pennsylvania: 1790-1801. Harrisburg: Pennsylvania Historical and Museum Commission, p. 138
  3. "PA Governor General Election". OurCampaigns. Retrieved July 3, 2012.
  4. "Pennsylvania Gubernatorial Election Returns 1793". House of Representatives of the Commonwealth of Pennsylvania. Retrieved July 3, 2012.
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