1896 United States presidential election in Texas
November 3, 1896
 
Nominee William Jennings Bryan William McKinley
Party Democratic Republican
Alliance Populist
Home state Nebraska Ohio
Running mate Arthur Sewall Garret Hobart
Electoral vote 15 0
Popular vote 370,434 167,520
Percentage 68.00% 30.75%
County Results
President before election

Grover Cleveland
Democratic

 Elected President

William McKinley
Republican

The 1896 United States presidential election in Texas took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. State voters chose 15 electors to the Electoral College, which selected the president and vice president.

Texas was won by the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate Arthur Sewall of Maine. Four electors cast their vice presidential ballots for Thomas E. Watson, Bryan's Populist running mate. They would defeat the Republican nominees, former Governor William McKinley of Ohio and his running mate corporate lawyer Garret Hobart of New Jersey. Bryan would win the state by a margin of 37.25%.

Bryan would beat McKinley in Texas again in 1900 and would later beat William Howard Taft in 1908.

Results

1896 United States presidential election in Texas[1]
Party Candidate Votes Percentage Electoral votes
Democratic William Jennings Bryan 370,434 68.00% 15
Republican William McKinley 167,520 30.75% 0
National Democratic John M. Palmer 5,046 0.93% 0
Prohibition Joshua Levering 1,786 0.33% 0
Totals 544,786 100.00% 15
Voter turnout —

See also

Notes

    References

    1. ↑ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Texas
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