1950 Iowa gubernatorial election
November 7, 1950
 
Nominee William S. Beardsley Lester S. Gillette
Party Republican Democratic
Popular vote 506,642 347,176
Percentage 59.10% 40.50%
County results

Beardsley:      50-60%      60-70%      70-80%

Gillette:      50–60%
Governor before election

William S. Beardsley
Republican

 Elected Governor

William S. Beardsley
Republican

The 1950 Iowa gubernatorial election was held on November 7, 1950. Incumbent Republican William S. Beardsley defeated Democratic nominee Lester S. Gillette with 59.10% of the vote.

Primary elections

Primary elections were held on June 5, 1950.[1]

Democratic primary

Candidates

Results

Democratic primary results[1]
Party Candidate Votes %
Democratic Lester S. Gillette 70,046
Democratic Myron J. Bennett 23,458
Total votes 93,504

Republican primary

Candidates

Results

Republican primary results[1]
Party Candidate Votes %
Republican William S. Beardsley (incumbent) 238,686 100.00
Total votes 238,686 100.00

General election

Candidates

Major party candidates

  • William S. Beardsley, Republican
  • Lester S. Gillette, Democratic

Other candidates

  • W. Raymond Picken, Prohibition
  • Howard H. Tyler, Independent

Results

1950 Iowa gubernatorial election[2]
Party Candidate Votes % ±%
Republican William S. Beardsley (incumbent) 506,642 59.10%
Democratic Lester S. Gillette 347,176 40.50%
Prohibition W. Raymond Picken 2,805 0.33%
Independent Howard H. Tyler 590 0.07%
Majority 159,466
Turnout 857,213
Republican hold Swing

References

  1. 1 2 3 "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1950. Retrieved April 8, 2020.
  2. ↑ "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1950. Retrieved April 8, 2020.
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